2x^2-4x+17/4=0

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Solution for 2x^2-4x+17/4=0 equation: 



2x^2-4x+17/4=0

We multiply all the terms by the denominator


2x^2*4-4x*4+17=0

Wy multiply elements

8x^2-16x+17=0

a = 8; b = -16; c = +17;
Δ = b2-4ac
Δ = -162-4·8·17
Δ = -288
Delta is less than zero, so there is no solution for the equation

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